Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

A broadcast AM transmitter radiates 50 kW of carrier power. What will be the radiated power at 85% modulation ?

Options:

150 kW

68 kW

85 kW

115 kW

Correct Answer:

68 kW

Explanation:

Pt = Pc [ 1 + \(\frac{\mu^2}{2}\) ]

Pc = 50 kW ; \(\mu\) = 85%

Pt = 68.1 kW