A broadcast AM transmitter radiates 50 kW of carrier power. What will be the radiated power at 85% modulation ?
Answer & explanation
Correct answer: option 2
Pt = Pc [ 1 + \(\frac{\mu^2}{2}\) ]
Pc = 50 kW ; \(\mu\) = 85%
Pt = 68.1 kW
A broadcast AM transmitter radiates 50 kW of carrier power. What will be the radiated power at 85% modulation ?
Correct answer: option 2
Pt = Pc [ 1 + \(\frac{\mu^2}{2}\) ]
Pc = 50 kW ; \(\mu\) = 85%
Pt = 68.1 kW