If sin 2θ = √3/2, then what is the value of tan θ ?

We are given that :-

sin 2θ = \(\frac{ √3 }{2}\)

{ we know, sin 60º = \(\frac{ √3 }{2}\) }

So,  2θ = 60º

θ = 30º

Now,

tan θ

= tan 30º 

= \(\frac{ 1 }{√3}\)