A bullet  of mass 2 g is having a charge of 2 mc. Through what potential difference must be accelerated, starting from rest, to acquire speed of 10 m/s?

50KV

Work done by electric field = change in kinetic energy

$ qV = \frac{1}{2} mv^2$

$\Rightarrow 2\times 10^{-6}= \frac{1}{2} \times 2\times 10^{-3}\times 10^2 $

$\Rightarrow V = 50KV$