A bullet of mass 2 g is having a charge of 2 micro coloumb. Through what potential difference must be accelerated, starting from rest, to acquire speed of 10 m/s?
Answer & explanation
Correct answer: option 4
Work done by electric field = change in kinetic energy
$ qV = \frac{1}{2} mv^2$
$\Rightarrow 2\times 10^{-6}= \frac{1}{2} \times 2\times 10^{-3}\times 10^2 $
$\Rightarrow V = 50KV$