Let P and Q be any two invertible matrices of the same order. Then Match List-I with List-II
Choose the correct answer from the options given below. |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(III), (B)-(I), (C)-(II), (D)-(IV) (A)-(II), (B)-(III), (C)-(IV), (D)-(I) (A)-(IV), (B)-(III), (C)-(I), (D)-(II) |
(A)-(III), (B)-(I), (C)-(II), (D)-(IV) |
The correct answer is Option (4) → 54
Key identity: $(AB)^{-1}=B^{-1}A^{-1}$ and $(A^{-1})^{-1}=A$ (A) $(PQ)^{-1}=Q^{-1}P^{-1}$ → (III) (B) $(P^{-1}Q)^{-1}=Q^{-1}(P^{-1})^{-1}=Q^{-1}P$ → (I) (C) $(PQ^{-1})^{-1}=(Q^{-1})^{-1}P^{-1}=QP^{-1}$ → (II) (D) $(P^{-1}Q^{-1})^{-1}=(Q^{-1})^{-1}(P^{-1})^{-1}=QP$ → (IV) Matching: (A)–(III), (B)–(I), (C)–(II), (D)–(IV) |