A function $f:[0,2] → R$ is strictly increasing in $(0,1)$ and strictly decreasing in $(1,2)$. Then which statement is TRUE? |
$f'(1)$ exists and is not equal to 0 $f'(x)=0$ for all $x \in[0,2]$ $f'(1)$ may not exist $f'(1)$ does not exist |
$f'(1)$ may not exist |
The correct answer is Option (3) - $f'(1)$ may not exist $⇒f'(1)=0$ or $f'(1)$ doesn't exist as differentiability is not considered at 1 |