CUET Preparation Today
$tan(cot^{-1}x)$ is equal to |
$\frac{\pi}{2}-x$ $\frac{1}{x}$ tan x none of these |
$\frac{1}{x}$ |
The correct answer is Option 2: $\frac{1}{x}$ $\theta = \cot^{-1} x$ $\cot\theta = x$ $\tan\theta = \frac{1}{\cot\theta} = \frac{1}{x}$ $\tan(\cot^{-1} x) = \frac{1}{x}$ The value is $\frac{1}{x}$. |
