Mohit is five times efficient as Rohit. If Mohit can complete a piece of work in 28 days less than Rohit, then in how many days can Rohit alone complete the same work?

35 days

Given,

Mohit is five times efficient as Rohit,

Mohit : Rohit = 5 : 1  (Efficiency)

⇒ Formula to be used,

\( { M}_{1 } \) x \( { D}_{1 } \)  = \( { M}_{2 } \) x \( { D}_{2 } \)

where, M = No. of men, D = No. of Days,

⇒ 5 x (D - 28) = 1 x D

⇒ 5D - 140 = D

⇒ 4D = 140,

⇒ D = 35 days,

Therefore, Rohit alone complete the same work in 35 days.