Mohit is five times efficient as Rohit. If Mohit can complete a piece of work in 28 days less than Rohit, then in how many days can Rohit alone complete the same work?
Answer & explanation
Correct answer: option 1
Given,
Mohit is five times efficient as Rohit,
Mohit : Rohit = 5 : 1 (Efficiency)
⇒ Formula to be used,
\( { M}_{1 } \) x \( { D}_{1 } \) = \( { M}_{2 } \) x \( { D}_{2 } \)
where, M = No. of men, D = No. of Days,
⇒ 5 x (D - 28) = 1 x D
⇒ 5D - 140 = D
⇒ 4D = 140,
⇒ D = 35 days,
Therefore, Rohit alone complete the same work in 35 days.