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Physics
Dual Nature of Radiation and Matter
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$K_{max} = \frac{hc}{\lambda} - \phi$
$\Rightarrow \phi = \frac{hc}{\lambda} - K_{max} = \frac{1240}{400} - 1.68 eV = 3.1 eV - 1.68 eV = 1.42 eV$