Consider the LPP, Min Z = x + 3y subject to the conditions:
$2 x+y ≥ 2,$
$x+2 y ≥ 4,$
$x ≥ 0, y ≥ 0$
Which of the following statement is correct about the feasible region of the above LPP.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → region is unbounded in first quadrant
$2 x+y ≥ 2⇒x+\frac{y}{2}≥1$
$x+2 y ≥ 4⇒\frac{x}{4}+\frac{y}{2}≥1$
$x,y ≥ 0$
