In parallelogram ABCD, angle A is greater than angle B by 10°, then measure of angle D is

85°

Note: In a parallelogram:

1. The opposite sides are parallel and equal.

2. The consecutive or adjacent angles are supplementary.

3. The opposite angles are always equal.

4. The two diagonals bisect each other.

Now, ATQ,

Let \(\angle\)B = x°, then \(\angle\)A = (x + 10)°

$⇒ x° + (x + 10)° = 180°$                     (as per above property no. 02)

$⇒ x° = 85°$

Now, as per above property (3),

⇒ \(\angle\)B = \(\angle\)D = x°

Hence, \(\angle\)D = 85°