The amount of water that must be added to 45 litres of pure milk at $2\frac{1}{2}$ litres for ₹120 so as to have mixture worth ₹36 a litre is : |
12 litres 5 litres 15 litres 20 litres |
15 litres |
The correct answer is Option (3) → 15 litres Initial Milk Quantity = $45 L$ Cost of Pure Milk = $₹48$ Desired cost of final mixture = $₹36/L$ $⇒\frac{45×48+x×0}{45+x}=36$ $⇒45×48=36×45+36x$ $⇒36x=2160-1620$ $⇒36x=540$ $⇒x=15L$ |