Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Linear Programming

Question:

A manufacturer has 3 machines I, II and III installed in his factory. Machines I and II are capable of being operated for atmost 12 hrs whereas machine III is capable to operate 5 hrs a day. He produced only two items M and N each requiring the use of all 3 machines. Number of hours for producing 1 unit of M and N each on the 3 machines are given below:

 Items 

 No. of hours in each machine 

I

II

III

M

1

2

1

N

2

1

1.25

He makes a profit of Rs. 600 on M and Rs. 400 on N. If x is the number of M items and y is the number of N items then,

A. $Z=600 x+400 y$
B. $x+2 y ≥ 12$
C. $x+\frac{5}{4} y ≤ 5$
D. $2 x+y ≤ 12$

Choose the correct answer from the options given below:

Options:

B, C and D only

A and B only

A and C only

C and D only

Correct Answer:

A and C only

Explanation:

The correct answer is Option (3) → A and C only

from question

$z=600x+400y$

constraints $(x,y≥0)$

from give hours 

for machine I, II

$(1+2)x+(2+1)y≤12$

$3x+3y≤12⇒x+y≤4$

also $x+1.25y≤5⇒x+\frac{5}{4}y≤5$

So we inform that only A and C are correct