A network of capacitors is given below. If, C1 = 8 μF and C2 = 12 μF, the equivalent capacitance of the network will be
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 20 μF
Each row of the network has two identical capacitors in series, and all four rows are joined between the same two terminals, so the rows are in parallel.
Two equal capacitors in series give half the value of one.
\( \displaystyle C_{\mathrm{row}} = \frac{C}{2} \)
\( \displaystyle C_1 \text{ row} = \frac{8\,\mu\mathrm{F}}{2} = 4\,\mu\mathrm{F} \)
\( \displaystyle C_2 \text{ row} = \frac{12\,\mu\mathrm{F}}{2} = 6\,\mu\mathrm{F} \)
Capacitances in parallel add.
\( C_{\mathrm{eq}} = 4 + 6 + 4 + 6 = 20\,\mu\mathrm{F} \)