Find the area bounded by the curves x2 = 4y and the straight line x = 4y - 2.

3/8 9/4 9/8 3/4

9/8

Solve x2 = 4y & x = 4y - 2  to get $A ≡(-1,\frac{1}{4})$ and B ≡ (2, 1) Required Area = Shaded Area = $\int\limits_{-1}^2(\frac{x+2}{4}-\frac{x^2}{4})dx=\frac{9}{8}$