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Find the area bounded by the curves x2 = 4y and the straight line x = 4y - 2. |
3/8 9/4 9/8 3/4 |
9/8 |
Solve x2 = 4y & x = 4y - 2 to get $A ≡(-1,\frac{1}{4})$ and B ≡ (2, 1)
Required Area = Shaded Area = $\int\limits_{-1}^2(\frac{x+2}{4}-\frac{x^2}{4})dx=\frac{9}{8}$ |
