The angle '$\theta$' between the transmission directions of polariser and analyser is varied, then the intensity 'I' of the light transmitted by analyser is correctly represented by

The correct answer is Option (3).

According to Malus's law -

$I=I_0\cos^2θ$

where,

I → Intensity of light

$I_0$ → Intensity of plane polarized light

θ → Angle between transmission axes of polarizer and analyses