At what distance from a convex lens of focal length 30 cm an object should be placed, so that the size of image be 1/4th of the object?
Answer & explanation
Correct answer: option 4
Image is real
∴ m = $\frac{v}{m}=-\frac{1}{4}$ or $v=-\frac{u}{4}$
As $\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
∴ $\frac{1}{(-u / 4)}-\frac{1}{u}=\frac{1}{30}$
$-\frac{4}{u}-\frac{1}{u}=\frac{1}{30}$
or u = -150 cm