If the length of diagonal of a cube is $8\sqrt{3}$ cm then what is its surface area?
Answer & explanation
Correct answer: option 3
We know that,
Diagonal of cube = \(\sqrt {3}\) × Side of cube
Surface area of cube = 6a2
Diagonal of cube = Side of cube \(\sqrt {3}\) = 8\(\sqrt {3}\)
= Side of cube = 8
Now, surface area of cube = 6(8)2 = 384 cm2.