The value of $\int\limits_{-2}^2\left(a x^3+b x+c\right) d x$ depends on
Answer & explanation
Correct answer: option 2
We have
$I=\int\limits_{-2}^2\left(a x^3+b x+c\right) d x$
$\Rightarrow I=a \int\limits_{-2}^2 x^3 d x+b \int\limits_{-2}^2 x d x+\int\limits_{-2}^2 c d x=a \times 0+b \times 0+4 c=4 c$
Hence, I depends on $c$ only.