In a $\triangle ABC$ if $\angle B=90^{\circ}$, BC = 8 cm and AB = 15 cm, then radius r of the incircle of $\triangle ABC$ is:
Answer & explanation
Correct answer: option 3
Triangle ABC is right angled at B.

AB = 15 cm
BC = 8 cm
Applying Pythagoras theorem,
AC^2=AB^2+BC^2=(15)^2+(8)^2=(225+64)=289
AC = 17
Since the circle is inscribed, quadrilateral made with the centre of the circle, O, Point B, P and Q make a square
BP=BQ=xcm.
Since the tangents to a circle from an exterior point are equal in length,
we have AR = AP and CR = CQ.
Now, AR = AP = (AB - BP) = (15 – x) cm
CR = CQ = (BC – BQ) = (8 - x) cm.
AC=AR+CR⇒17=(15–x)+(8–x)⇒2x=6⇒x=3.
Hence, the radius of the inscribed circle is 3 cm.
The correct answer is Option (3) → 3 cm