Let $A = \{x∈R:-1≤x≤1\}$. Then, the mapping $f:A→A$ given by $f (x) = x|x|$, is
Answer & explanation
Correct answer: option 3
We have,
$f(x)=x|x|=\left\{\begin{matrix}x^2,&x≥0\\-x^2,&x<0\end{matrix}\right\}$
The graph f (x) is shown in Fig.
Clearly, f is bijective.