A contract is to be completed in 75 days and 187 men are to work 15 hours per day. After 65 days, $\frac{3}{5}$ of the work is completed. How many additional men may be employed, so that the work may be completed in time, each man now working 17 hours per day?
Answer & explanation
Correct answer: option 3
Formula to be used here,
\(\frac{M_1\;×\;D_1\;×\;H_1}{M_2\;×\;D_2\;×\;H_2}\)=\(\frac{W_1}{W_2}\)
where, M = No. of men, D = No. of days, H = No. of hours, W = Work
⇒ Putting values,
⇒ \(\frac{187\;×\;65\;×\;15}{M_2\;×\;10\;×\;17}\) = \(\frac{3/5}{2/5}\)
⇒ \( { M}_{2 } \) = 715,
⇒ Extra Men needed = 715 - 187 = 528 men.