Target Exam

CUET

Subject

Mathematics

Chapter

Relations and Functions

Question:

If $(x + 1,y-2) = (3,1)$, find the values of x and y.

Options:

$x = 2, y = 3$

$x = 1, y = 3$

$x = 3, y = 2$

$x = 4, y = 3$

Correct Answer:

$x = 2, y = 3$

Explanation:

The correct answer is Option (1) → $x = 2, y = 3$

Since the ordered pairs are equal, the corresponding elements are equal.

Therefore $x + 1 = 3$ and $y-2=1$

Solving we get $x = 2$ and $y = 3$.