If $(x + 1,y-2) = (3,1)$, find the values of x and y. |
$x = 2, y = 3$ $x = 1, y = 3$ $x = 3, y = 2$ $x = 4, y = 3$ |
$x = 2, y = 3$ |
The correct answer is Option (1) → $x = 2, y = 3$ Since the ordered pairs are equal, the corresponding elements are equal. Therefore $x + 1 = 3$ and $y-2=1$ Solving we get $x = 2$ and $y = 3$. |