Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

A dipole of dipole moment p is kept at the centre of a ring of radius R and charge Q. The dipole moment has direction along the axis of the ring. The resultant force on the ring due to the dipole is

Options:

Zero

$\frac{kpQ}{R^3}$

$\frac{2kpQ}{R^3}$

$\frac{kpQ}{R^3}$ only if the charge is uniformly distributed on the ring

Correct Answer:

$\frac{kpQ}{R^3}$

Explanation:

$ F = p \frac{dE}{dx} $

$ E = \frac{kQ}{2{R^2+x^2}^{3/2}}$ 

$\frac{dE}{dx} _{ x= 0 }= \frac{kQ}{R^3}$

$\Rightarrow F =  p \frac{dE}{dx} = \frac{kpQ}{R^3}$