What is the area (in sq cm) of a rectangle of perimeter 52 cm and breadth 20 cm?
Answer & explanation
Correct answer: option 3
Perimeter of rectangle = 2 (l + b)
52 = 2 (l + 20)
l = \(\frac{52}{2}\) – 20 = 6 cm.
area = l × b = 6 × 20 = 120 cm2
What is the area (in sq cm) of a rectangle of perimeter 52 cm and breadth 20 cm?
Correct answer: option 3
Perimeter of rectangle = 2 (l + b)
52 = 2 (l + 20)
l = \(\frac{52}{2}\) – 20 = 6 cm.
area = l × b = 6 × 20 = 120 cm2