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If a straight conductor of length 0.5 m is moved with a speed of $6 ms^{-1}$ perpendicular to direction of a magnetic field of $1 Wb m^{-2}$, the emf induced is: |
18.0 V 3.0 V 1.5 V 9.0 V |
3.0 V |
The correct answer is Option (2) → 3.0 V According to faraday's law of emf - $ε=B.l.v$ where, B = Magnetic field v = velocity of charged particle $=1×0.5×6$ $=3V$ |
