If a straight conductor of length 0.5 m is moved with a speed of \( 6\,\mathrm{m\,s^{-1}} \) perpendicular to direction of a magnetic field of \( 1\,\mathrm{Wb\,m^{-2}} \), the emf induced is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 3.0 V
A conductor of length l moving with speed v at right angles to a field B has a motional emf \( \varepsilon = Blv \), because the magnetic force on its free charges separates them along the conductor.
\( \varepsilon = Blv = 1\,\mathrm{Wb\,m^{-2}}\times0.5\,\mathrm{m}\times6\,\mathrm{m\,s^{-1}} = 3.0\,\mathrm{V} \)