If a straight conductor of length 0.5 m is moved with a speed of $6 ms^{-1}$ perpendicular to direction of a magnetic field of $1 Wb m^{-2}$, the emf induced is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 3.0 V
According to faraday's law of emf -
$ε=B.l.v$
where,
B = Magnetic field
v = velocity of charged particle
$=1×0.5×6$
$=3V$