A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many liters of the later must be mixed with 3 liters of the former so that the resulting mixture may contain equal quantities of wine and water.
Answer & explanation
Correct answer: option 1
Wine : Water : Total
1st : 3 : 2 : 5 )× 18 = 90
2nd : 4 : 5 : 9 )× 10 = 90
New: 1 : 1 : 2 )× 45 = 90
Use alligation method on water:
