A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many liters of the later must be mixed with 3 liters of the former so that the resulting mixture may contain equal quantities of wine and water.

\(5\frac{2 }{5}\)

           Wine   :    Water   :    Total

1st :       3      :        2      :       5     )× 18 = 90

2nd :      4      :        5      :       9     )× 10 = 90

New:      1      :        1      :       2     )× 45 = 90

Use alligation method on water: