If $f(x)=x-\left|x-x^2\right|, x \in[-1,1]$. Then the number of points at which f(x) is discontinuous
Answer & explanation
Correct answer: option 1
Given function can be written as
$f(x)=\left\{\begin{array}{l}2 x-x^2 &-1 \leq x \leq 0 \\ x^2 &0 \leq x \leq 1\end{array}\right.$
Hence (1) is the correct answer.