If a certain sum becomes three times in 4 years at compound interest, then in how many years, will it become 9 times? |
12 10 8 6 |
8 |
The correct answer is Option (3) → 8 Step 1: Let the principal = P, rate = r
$P(1+r)^4 = 3P ⟹ (1+r)^4 = 3$ Step 2: Find the number of years for it to become 9 times
$P(1+r)^n = 9P ⟹ (1+r)^n = 9$ Step 3: Express 9 in terms of 3 $(1+r)^n = 9 = 3^2 = [(1+r)^4]^2$ $(1+r)^n = [(1+r)^4]^2 ⟹ n = 4 \times 2 = 8$ |