Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Thermodynamics

Question:

A spherical black body with a radius of 12 cm radiates 450 watt power at 500 K. If the radius were halved and the temperature doubled, the power radiated in watt would be : 

Options:

1800

225

450

1000

Correct Answer:

1800

Explanation:

Rate of power loss : r ∝ R2T4

\(\frac{r_1}{r_2} = \frac{R_1^2T_1^2}{R_2^2T_2^2} \)

\(\frac{450}{r_2} = 4 × \frac{1}{16} \)

\(r_2\) = 1800 W