The solution of the differential equation $\frac{dy}{dx}=\frac{6}{x^2}$; y(1) = 3 is:

$y=9+\frac{6}{x}$ $y=9-\frac{6}{x}$ $y=-9+\frac{6}{x}$ $y=-3-\frac{6}{x}$

$y=9-\frac{6}{x}$

The correct answer is Option (2) - $y=9-\frac{6}{x}$