If $Δ=\begin{vmatrix}my+nz&mq+

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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Determinants

Question:

If $Δ=\begin{vmatrix}my+nz&mq+nr&mb+nc\\kz-mx&kr-mp&kb+ma\\nx+ky&np+kq&na+kb\end{vmatrix}$ then Δ is equal to

Options:

≠ 0

f(x,y,z)

None of these

Correct Answer:

Explanation:

We find that $-Δ=\begin{vmatrix}x&y&z\\p&q&r\\a&b&c\end{vmatrix}\begin{vmatrix}0&m&n\\-m&0&k\\-n&-k&0\end{vmatrix}=0$.

Hence (A) is the correct answer.