In a rummy game, 2 cards are drawn from a pack of 52 cards. What is the probability that both the cards are of red colour? |
\(\frac{13}{102}\) \(\frac{13}{51}\) \(\frac{25}{102}\) \(\frac{25}{51}\) |
\(\frac{25}{102}\) |
The number of red cards = 26 The number of ways of selection 2 red cards out of 26 cards = 26C2 = \(\frac{26\;×\;25}{2}\) = 13 × 25 The number of ways of selection 2 cards out of 52 cards = 52C2 = \(\frac{52\;×\;51}{2}\) = 26 × 51 The reqd. probability = \(\frac{13\;×\;25}{ 26\;×\;51}\) = \(\frac{25}{102}\) Hence, option C is correct. |