A tree gets broken at a point due to a storm and its top touches the ground at a distance 30 m from the base of the tree with an angle 30° with the gound.  What is the height of the tree?

30\(\sqrt {3}\)

AB = Tan 30° × BC

AB = \(\frac{1}{\sqrt {3}}\) × 30 = 10 \(\sqrt {3}\)

AC = \(\frac{AB}{Sin\;30°}\) = \(\frac{10\sqrt {3}}{\frac{1}{2}}\)= 20\(\sqrt {3}\)

Height of the tree = AB + AC = 10\(\sqrt {3}\) + 20\(\sqrt {3}\) = 30\(\sqrt {3}\)