If $\sin 3x = \cos (3x - 45^\circ), 0^\c

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If $\sin 3x = \cos (3x - 45^\circ), 0^\circ < 3x < 90^\circ$, then x is equal to:

Options:

45°

22.5°

35°

27°

Correct Answer:

22.5°

Explanation:

We are given that ,

sin3x = cos (3x - 45º )

{ If A + B = 90º , Then sinA = cosB }

So, 3x + 3x - 45º = 90º

6x = 135º

x = 22.5º