The direction ratios of the line perpendicular to the lines $\frac{x-7}{2}=\frac{y+17}{-3}=\frac{z-6}{1}$ and $\frac{x+5}{1}=\frac{y+3}{2}=\frac{z-4}{-2}$ are proportional to

4, 5, 7 4, -5, 7 4, -5, -7 -4, 5, 7

4, 5, 7

Let the direction ratios of the line perpendicular to the given lines be proportional to a, b, c. Then, $2a - 3b + c = 0 $ and $a + 2b -2c=0$ $∴ \frac{a}{4}=\frac{b}{5}=\frac{c}{7}⇒ a : b : c = 4 : 5 : 7 $