$\int\left(x+\frac{1}{x}\right)^2 dx$ equals :
Answer & explanation
Correct answer: option 2
$I=\int\left(x+\frac{1}{x}\right)^2 d x$
so $I=\int x^2+\frac{1}{x^2}+2 d x$
$=\frac{x^3}{3}-\frac{1}{x}+2 x+c$
$\int\left(x+\frac{1}{x}\right)^2 dx$ equals :
Correct answer: option 2
$I=\int\left(x+\frac{1}{x}\right)^2 d x$
so $I=\int x^2+\frac{1}{x^2}+2 d x$
$=\frac{x^3}{3}-\frac{1}{x}+2 x+c$