Practicing Success
If $sec θ + tan θ = 2 + \sqrt{5}$ and θ is an acute angle, then the value of sin θ is: |
$\frac{2\sqrt{5}}{5}$ $\frac{3}{5}$ $\frac{\sqrt{5}}{5}$ $\frac{1}{5}$ |
$\frac{2\sqrt{5}}{5}$ |
We know , sec²θ - tan²θ = 1 So , secθ - tanθ = \(\frac{1 }{secθ + tanθ }\) ATQ, secθ + tanθ = 2 + √5 ------(1) So, secθ - tanθ = \(\frac{1 }{2 + √5 }\) = \(\frac{1 }{2 + √5 }\) × \(\frac{2 - √5 }{2 - √5 }\) = √5 - 2 --------(2) Adding 1 and 2 2 secθ = 2√5 cosθ = \(\frac{1 }{ √5 }\) We know , sin²θ + cos²θ = 1 sin²θ + \(\frac{1 }{ 5 }\) = 1 sinθ = \(\frac{2 }{ √5 }\) = \(\frac{2 √5}{ 5 }\)
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