In the figure, Two circles with centres P and Q touch externally at R. Tangents AT and BT meet the common tangent TR at T. If AP = 6 cm and PT = 10 cm, then BT = ?
Answer & explanation
Correct answer: option 2
By using pythagoras theorem,
PT² = PA² + AT²
10² = 6² + AT²
AT² = 100 - 36 = 64
AT² = 64
AT = 8 cm
We know, Tangents from a common point to the same circle is of same length,
i.e. TA = TR & TR = TB
⇒ TA = TR = TB
As, TA = 8 cm
⇒ TB = 8 cm