The following Pie chart represents the percentage-wise distribution of 800 students of class XII in a school in six different sections A, B, C, D, E and F.

The table given below shows the number of girls of class XII in six different sections A, B, C, D, E and F.

The total number of girls in sections B, C and D together is what percent more than the total number of boys in sections A, B and D together?

76.25

20% = \(\frac{1}{5}\)

Total number of boys in A , B & D =  (\(\frac{1}{5}\) × 800 - 102 ) + (  \(\frac{18}{100}\) × 800  - 80 ) + (  \(\frac{17}{100}\) × 800 - 98 )

= 58 + 64 + 38

= 160

Total number of girls in B , C & D = 80 +  104 + 98 = 282 

Required percentage = \(\frac{282 - 160}{160}\) × 100

= \(\frac{122}{160}\) × 100

= 76.25%