The following Pie chart represents the percentage-wise distribution of 800 students of class XII in a school in six different sections A, B, C, D, E and F.
The table given below shows the number of girls of class XII in six different sections A, B, C, D, E and F.
|
Section |
A |
B |
C |
D |
E |
F |
|
No. of girls |
102 |
80 |
104 |
98 |
0 |
60 |
The total number of girls in sections B, C and D together is what percent more than the total number of boys in sections A, B and D together?
Answer & explanation
Correct answer: option 2
20% = \(\frac{1}{5}\)
Total number of boys in A , B & D = (\(\frac{1}{5}\) × 800 - 102 ) + ( \(\frac{18}{100}\) × 800 - 80 ) + ( \(\frac{17}{100}\) × 800 - 98 )
= 58 + 64 + 38
= 160
Total number of girls in B , C & D = 80 + 104 + 98 = 282
Required percentage = \(\frac{282 - 160}{160}\) × 100
= \(\frac{122}{160}\) × 100
= 76.25%