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In a meter bridge with a standard resistance of 15 Ω in the right gap, the ratio of balancing length is 3:2. What is the value of the other resistance? |
25 Ω 15 Ω 15.7 Ω 22.5 Ω |
22.5 Ω |
$\text{In balanced meter bridge} \frac{R_2}{R_1} = \frac{l_2}{l_1}$ $\Rightarrow R_2 = \frac{l_2\times R_1}{l_1} = \frac{3\times 15}{2}\Omega = 22.5\Omega$ |
