By using equations of the line $\frac{x+1}{2}=\frac{y}{3}=\frac{z-3}{6}$ and the plane $10 x+2 y-11 z-3=0$, answer the following questions.
Distance of plane 10x + 2y – 11z – 3 = 0, from the origin is:
Answer & explanation
Correct answer: option 4
O(0, 0, 0)
Distance = $\frac{|10 \times 0+2 \times 0-11 \times 0-3|}{\sqrt{10^2+2^2+(-11)^2}}=\frac{3}{15}=\frac{1}{5}$
Option: D