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CUET
General Test
Numerical Ability
The least number which when divided by 12, 15, 20 & 54 leaves remainder of 4 in each case is:
544
536
364
540
We have to find the L.C.M of 12, 15, 20 and 54
L.C.M = 540
The least number is 540 + 4 = 544