The value of \(\int_{0}^{1} { e }^{ -4x } dx\)1\[\frac{{ e }^{ 4 } -1}{4}\]2\[\frac{-{ e }^{ 4 } +1}{4}\]3\[\frac{-{ e }^{ -4 } +1}{4}\]4\[\frac{{ e }^{- 4 } -1}{4}\]Answer & explanation+Correct answer: option 3the integral will be \[\frac{{ e }^{ -4x } }{-4}\]
