Practicing Success
Practicing Success
CUET Preparation Today
| The value of \(\int_{0}^{1} { e }^{ -4x } dx\) |
\[\frac{{ e }^{ 4 } -1}{4}\] \[\frac{-{ e }^{ 4 } +1}{4}\] \[\frac{-{ e }^{ -4 } +1}{4}\] \[\frac{{ e }^{- 4 } -1}{4}\] |
| \[\frac{-{ e }^{ -4 } +1}{4}\] |
| the integral will be \[\frac{{ e }^{ -4x } }{-4}\] |
