What is the angle of dip at a place where the horizontal component of the earth’s magnetic field is equal to the vertical component?
Answer & explanation
Correct answer: option 3
The angle of dip is given by $\delta = tan^{-1}(\frac{B_V}{B_H}) = tan^{-1}1 = 45^o$
The angle of dip at a place where horizontal component of earth's magnetic field is equal to the vertical component is 45o.