Two charges -10 nC and +10 nC are separated by 6 mm. What is the magnitude of the dipole moment?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $6 × 10^{-11} Cm$
The Dipole Moment $(\vec p)$ is,
$\vec p=q×d$
$=(10×10^{-9})×(6×10^{-3})$
$=6×10^{-11}Cm$