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Two charges -10 nC and +10 nC are separated by 6 mm. What is the magnitude of the dipole moment? |
$6 × 10^{-12} C m$ $6 × 10^{-11} Cm$ $6 × 10^{12} C m$ $6 × 10^{-10} C m$ |
$6 × 10^{-11} Cm$ |
The correct answer is Option (2) → $6 × 10^{-11} Cm$ The Dipole Moment $(\vec p)$ is, $\vec p=q×d$ $=(10×10^{-9})×(6×10^{-3})$ $=6×10^{-11}Cm$ |
