Two charges −10 nC and +10 nC are separated by 6 mm. What is the magnitude of the dipole moment?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( 6\times10^{-11}\,\mathrm{C\,m} \)
The electric dipole moment has magnitude p = q × 2a, the size of either charge times their separation.
\( q = 10\,\mathrm{nC} = 10\times10^{-9}\,\mathrm{C},\quad 2a = 6\,\mathrm{mm} = 6\times10^{-3}\,\mathrm{m} \)
\( p = (10\times10^{-9})(6\times10^{-3}) = 6\times10^{-11}\,\mathrm{C\,m} \)