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CUET
-- Mathematics - Section B1
Matrices
If A and B are two matrices such that $AB = A$ and $BA = B$, then $B^2$ is equal to
B
A
1
0
We have, $AB = A$ and $BA = B$
$∴B^2 = BB$
$⇒B^2 = (BA) B$ $[∵ BA = B]$
$⇒B^2 = B (AB)$ $[∵ AB = A]$
$⇒B^2 = B$ $[∵ BA = B]$