The magnitude and direction of the current in the circuit shown will be:
Answer & explanation
Correct answer: option 4
i = $\frac{\text { Net emf }}{\text { Net resistance }}=\frac{10-4}{1+2+3}$ = 1 A from a to e
The magnitude and direction of the current in the circuit shown will be:
Correct answer: option 4
i = $\frac{\text { Net emf }}{\text { Net resistance }}=\frac{10-4}{1+2+3}$ = 1 A from a to e