The magnitude and direction of the current in the circuit shown will be:

$\frac{7}{3}$A from a to e $\frac{7}{3}$A from b to e 1 A from b to e 1 A from a to e

1 A from a to e

i = $\frac{\text { Net emf }}{\text { Net resistance }}=\frac{10-4}{1+2+3}$ = 1 A from a to e