Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Mensuration: 3D

Question:

A 64 cm wide path is made around a circular garden having a diameter of 10 metres. The area (in m?) of the path is closest to: $(take \pi= \frac{22}{7})$

Options:

10

11

15

9

Correct Answer:

10

Explanation:

We know that,

Area of path = Outer area - Inner area

Length of circular path = 64cm

Diameter of garden = 10m = 1000 cm

Then the radius of garden = 500 cm = Inner radius

Outer radius =  564 cm

Now, according to the question,

= \(\frac{22}{7}\) × (5642 - 5002)

= \(\frac{22}{7}\) × (564 + 500)(564 - 500)

= \(\frac{22}{7}\) × (1064)(64) = 21.4016 m2