A convex mirror has a focal length f. A real object is placed at a distance fin front of it from the pole, produces an image at

$f/2$

$ \text { u = -f , F = +f }$

$ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} $

$ \frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{f} - \frac{1}{-f} = \frac{2}{f} $

$ v = \frac{f}{2} \text{ Behind the Mirror}$