Practicing Success
Namrata travels from her house at 5\(\frac{1}{2}\) km/h and reaches her school 14 minutes late. The next day she travels at 6\(\frac{1}{2}\) and reaches her school 10 minutes early. What is the distance between her house and the school? |
14.3 Km 20.5 Km 13.4 Km 43.1 Km |
14.3 Km |
D = \(\frac{S_1 × S_2}{S_1 - S_2}\) × Total time interval D = \(\frac{11}{2}\) × \(\frac{13}{2}\) × \(\frac{24}{60}\) = 14.3 Km |